Why fission releases about 200 MeVविखंडन में लगभग 200 MeV क्यों निकलती हैWhy fission releases about 200 MeV
NCERT Section 13.7.1 · Class 12 Physics · Chapter 13 · interactive diagram
Read Chapter 13 with this diagramइस डायग्राम के साथ अध्याय 13 पढ़ेंIs diagram ke saath Ch 13 padhiyeAll Physics diagramsसभी भौतिकी डायग्रामSaare Physics diagrams
Parts and what they mean
- Zero of energy: free nucleons (ऊर्जा का शून्य: मुक्त न्यूक्लिऑन) — Take the energy of 240 separate, resting nucleons as zero.
- A = 240 nucleus (A = 240 नाभिक) — E_bn ≈ 7.6 MeV, so its energy is 240 × 7.6 = 1824 MeV below the free nucleons.
- Two A = 120 nuclei (दो A = 120 नाभिक) — E_bn ≈ 8.5 MeV for each fragment: more tightly bound, so a lower energy level.
- Energy released (मुक्त ऊर्जा) — Gain in binding energy = 240 × (8.5 − 7.6) = 240 × 0.9 = 216 MeV ≈ 200 MeV per fission.
- Binding energy (बंधन ऊर्जा) — The depth below the free-nucleon line is the total binding energy E_b.
Original diagram drawn by Simple Learning Hub, based on NCERT Section 13.7.1. Report a mistake