What you will learn in this chapter
- Explain Mendel's monohybrid and dihybrid crosses and derive the 3:1 and 9:3:3:1 ratios using Punnett squares.
- State the laws of dominance, segregation and independent assortment, and use a test cross to find an unknown genotype.
- Differentiate incomplete dominance, co-dominance, multiple allelism, pleiotropy and polygenic inheritance with NCERT examples.
- Explain the chromosomal theory of inheritance, linkage and recombination (Morgan's work).
- Describe sex determination in humans, birds, grasshopper and honey bee.
- Analyse pedigrees and describe Mendelian and chromosomal disorders.
📘 Open this chapter on NCERT official website (ncert.nic.in) · The same NCERT chapter is taught in both CBSE and UP Board.
Principles of Inheritance and Variation — Notes
🖼️ Diagrams are now right inside the notes. Tap any picture to zoom and see the name and job of each part; 🧊 3D opens the 3D model.डायग्राम अब नोट्स के अंदर ही हैं। किसी भी चित्र पर टैप करें — ज़ूम करें और हर भाग का नाम व कार्य देखें; 🧊 3D से 3D मॉडल खुलता है।Diagrams ab notes ke andar hi hain. Kisi bhi picture par tap kijiye — zoom kijiye aur har part ka naam aur kaam dekhiye; 🧊 3D se 3D model khulta hai.
Revise these first (prerequisites)
- Basic meaning of gene, allele, chromosome
- Meiosis: homologous chromosomes separate (Class 11)
- The simple idea of dominant vs recessive (Class 10)
- Basic probability / multiplication (for the Punnett square)
Why do children look like their parents?
Characters (such as height, eye colour) pass from parents to offspring — this is called inheritance / वंशागति. At the same time, siblings are not identical — this is variation / विविधता. This chapter explains both.
Gene and allele
Each character is controlled by a gene, and each gene can exist in two forms — these are called alleles (विकल्पी), e.g., T (tall) and t (dwarf). Every organism has 2 alleles of a gene — one from the mother and one from the father.
Dominant and recessive
When two different alleles are together (Tt), the one that is expressed is dominant (प्रभावी) (T), and the one that stays hidden is recessive (अप्रभावी) (t). A recessive trait shows only when both alleles are recessive (tt). It is like two people talking, where one voice is so loud that the other cannot be heard at all.
Monohybrid cross (Punnett square)एकसंकर संकरण (पुनेट वर्ग)Monohybrid cross (Punnett square)NCERT Figs 4.3–4.4Tall TT × dwarf tt → F1 all Tt tall; F2 from the Punnett square: 3 tall : 1 dwarf, genotypes 1 TT : 2 Tt : 1 tt.लंबा TT × बौना tt → F1 सभी Tt लंबे; पनेट वर्ग से F2: 3 लंबे : 1 बौना, जीनोटाइप 1 TT : 2 Tt : 1 tt।Tall TT × dwarf tt → F1 sab Tt tall; Punnett square se F2: 3 tall : 1 dwarf, genotypes 1 TT : 2 Tt : 1 tt. Mendel's experiment
Gregor Mendel performed experiments on the garden pea for 7 years (1856–1863). When he crossed tall (TT) × dwarf (tt), all F1 plants were tall, and on selfing the F1, the F2 showed tall : dwarf = 3 : 1. This showed that the dwarf factor had not disappeared; it was only hidden.
Monohybrid cross (Punnett square)एकसंकर संकरण (पुनेट वर्ग)Monohybrid cross (Punnett square)NCERT Figs 4.3–4.4Tall TT × dwarf tt → F1 all Tt tall; F2 from the Punnett square: 3 tall : 1 dwarf, genotypes 1 TT : 2 Tt : 1 tt.लंबा TT × बौना tt → F1 सभी Tt लंबे; पनेट वर्ग से F2: 3 लंबे : 1 बौना, जीनोटाइप 1 TT : 2 Tt : 1 tt।Tall TT × dwarf tt → F1 sab Tt tall; Punnett square se F2: 3 tall : 1 dwarf, genotypes 1 TT : 2 Tt : 1 tt. Punnett square = a table
A Punnett square is a simple table: gametes of one parent along the top, gametes of the other along the side, and their combinations in the boxes. Tt × Tt → TT, Tt, Tt, tt, i.e., a 1 : 2 : 1 genotypic and 3 : 1 phenotypic ratio. With a little practice, this becomes the easiest scoring part.
Monohybrid cross (Punnett square)एकसंकर संकरण (पुनेट वर्ग)Monohybrid cross (Punnett square)NCERT Figs 4.3–4.4Tall TT × dwarf tt → F1 all Tt tall; F2 from the Punnett square: 3 tall : 1 dwarf, genotypes 1 TT : 2 Tt : 1 tt.लंबा TT × बौना tt → F1 सभी Tt लंबे; पनेट वर्ग से F2: 3 लंबे : 1 बौना, जीनोटाइप 1 TT : 2 Tt : 1 tt।Tall TT × dwarf tt → F1 sab Tt tall; Punnett square se F2: 3 tall : 1 dwarf, genotypes 1 TT : 2 Tt : 1 tt. How is sex determined?
In humans, females are XX and males are XY. Every ovum carries an X, whereas a sperm carries either X or Y — so the sex of the baby is decided by the sperm. This is a biological fact; it is not the mother's 'fault' in any way.
Sex determination in humans (XY)मनुष्य में लिंग निर्धारण (XY)Sex determination in humans (XY)NCERT Fig 4.12Mother gives only X eggs; father gives X or Y sperms (50 : 50). So the sperm decides the child's sex.माता केवल X अंडाणु देती है; पिता X या Y शुक्राणु (50 : 50)। इसलिए संतान का लिंग शुक्राणु तय करता है।Maa sirf X eggs deti hai; pita X ya Y sperms (50 : 50). Isliye bachche ka sex sperm tay karta hai.
Quick check ✔
1. What will be the F2 phenotypic ratio in a Tt × Tt cross?
2. When does a recessive trait appear?
Basics clear? Now move on to Learn in Detail 👆
As per NCERT 2026-27 — every point you need for the board exam.
Heredity & variation
Inheritance = passing of characters from parents to offspring. Variation = difference of offspring from parents. Mendel experimented on garden pea (Pisum sativum) from 1856–1863; he chose 7 contrasting traits.
Monohybrid cross
Tall (TT) × dwarf (tt) → F1 all Tall (Tt). F1 selfing → F2 phenotypic ratio 3:1, genotypic ratio 1:2:1. Punnett square: Reginald C. Punnett.
Monohybrid cross (Punnett square)एकसंकर संकरण (पुनेट वर्ग)Monohybrid cross (Punnett square)NCERT Figs 4.3–4.4Tall TT × dwarf tt → F1 all Tt tall; F2 from the Punnett square: 3 tall : 1 dwarf, genotypes 1 TT : 2 Tt : 1 tt.लंबा TT × बौना tt → F1 सभी Tt लंबे; पनेट वर्ग से F2: 3 लंबे : 1 बौना, जीनोटाइप 1 TT : 2 Tt : 1 tt।Tall TT × dwarf tt → F1 sab Tt tall; Punnett square se F2: 3 tall : 1 dwarf, genotypes 1 TT : 2 Tt : 1 tt. Mendel's laws
Law of Dominance: factors occur in pairs, one dominant and the other recessive. Law of Segregation: alleles separate during gamete formation (law of purity of gametes). Law of Independent Assortment: two pairs of traits segregate independently (from dihybrid cross).
Test cross
Crossing a dominant-phenotype individual (TT or Tt?) with a recessive parent (tt). If the result is 1:1, it is heterozygous; if all are dominant, it is homozygous.
Incomplete dominance
Snapdragon / dog flower (Antirrhinum): red (RR) × white (rr) → F1 pink (Rr). In F2, both the phenotypic and genotypic ratios are 1:2:1.
Incomplete dominance in snapdragonस्नैपड्रैगन में अपूर्ण प्रभाविताIncomplete dominance in snapdragonNCERT Fig 4.6RR red × rr white → F1 Rr pink (in between). F2: 1 red : 2 pink : 1 white — phenotype ratio = genotype ratio.RR लाल × rr सफ़ेद → F1 Rr गुलाबी (बीच का)। F2: 1 लाल : 2 गुलाबी : 1 सफ़ेद — फीनोटाइप अनुपात = जीनोटाइप अनुपात।RR red × rr white → F1 Rr pink (beech ka). F2: 1 red : 2 pink : 1 white — phenotype ratio = genotype ratio. Co-dominance & multiple alleles
ABO blood group: gene I has 3 alleles — Iᴬ, Iᴮ, i. Iᴬ and Iᴮ are co-dominant (AB blood group), i is recessive. 6 genotypes, 4 phenotypes. 3 alleles = multiple alleles.
ABO blood groups: multiple alleles and co-dominanceABO रुधिर वर्ग: बहुयुग्मविकल्पी और सह-प्रभाविताABO blood groups: multiple alleles and co-dominanceNCERT Table 4.23 alleles (Iᴬ, Iᴮ, i) → 6 genotypes → 4 blood groups. Iᴬ and Iᴮ are dominant over i; together (AB) both show = co-dominance.3 युग्मविकल्पी (Iᴬ, Iᴮ, i) → 6 जीनोटाइप → 4 रुधिर वर्ग। Iᴬ, Iᴮ, i पर प्रभावी; साथ हों (AB) तो दोनों दिखते हैं = सह-प्रभाविता।3 alleles (Iᴬ, Iᴮ, i) → 6 genotypes → 4 blood groups. Iᴬ aur Iᴮ, i par dominant; dono saath (AB) to dono dikhte hain = co-dominance. Pleiotropy & polygenic
Pleiotropy: one gene, many effects (phenylketonuria). Polygenic: many genes together control one trait (human skin colour, height).
Dihybrid cross
Round yellow (RRYY) × wrinkled green (rryy) → F2 9:3:3:1. This gave the Law of Independent Assortment.
Dihybrid cross (9:3:3:1)द्विसंकर संकरण (9:3:3:1)Dihybrid cross (9:3:3:1)NCERT Fig 4.7Two traits sort independently: F2 gives 9 : 3 : 3 : 1 — basis of the law of independent assortment.दो लक्षण स्वतंत्र रूप से बँटते हैं: F2 में 9 : 3 : 3 : 1 — स्वतंत्र अपव्यूहन के नियम का आधार।Do traits alag-alag bat-te hain: F2 mein 9 : 3 : 3 : 1 — law of independent assortment ka aadhaar. Chromosomal theory
Sutton and Boveri linked genes to chromosomes. Morgan worked on Drosophila → linkage (genes on the same chromosome are inherited together) and recombination. Alfred Sturtevant: gene mapping using recombination frequency.
🧊 See in 3D: chromosome3D में देखें: गुणसूत्र3D dekhiye: chromosome
Sex determination
Humans: XX female, XY male (male heterogametic — the sex of the child is decided by the father's sperm). Grasshopper: XO type. Birds: ZW female (female heterogametic), ZZ male. Honey bee: haplodiploid — fertilised egg = female (2n), unfertilised = male drone (n).
Sex determination in humans (XY)मनुष्य में लिंग निर्धारण (XY)Sex determination in humans (XY)NCERT Fig 4.12Mother gives only X eggs; father gives X or Y sperms (50 : 50). So the sperm decides the child's sex.माता केवल X अंडाणु देती है; पिता X या Y शुक्राणु (50 : 50)। इसलिए संतान का लिंग शुक्राणु तय करता है।Maa sirf X eggs deti hai; pita X ya Y sperms (50 : 50). Isliye bachche ka sex sperm tay karta hai. Mutation & pedigree
Mutation = a change in the DNA sequence. Example of a point mutation: sickle cell anaemia. Frameshift: insertion/deletion of bases. Pedigree analysis is used to track the inheritance of a trait in a family.
Symbols used in human pedigree analysisमानव वंशावली विश्लेषण में प्रयुक्त प्रतीकSymbols used in human pedigree analysisNCERT Fig 4.13 (symbols)Learn these symbols first: square = male, circle = female, shaded = affected, double line = marriage between relatives.पहले ये प्रतीक याद करें: वर्ग = नर, वृत्त = मादा, भरा = प्रभावित, दोहरी रेखा = रिश्तेदारों में विवाह।Pehle ye symbols yaad kijiye: square = male, circle = female, shaded = affected, double line = relatives mein shaadi. Mendelian disorders
Haemophilia (sex-linked recessive, blood fails to clot; Queen Victoria's pedigree). Colour blindness (sex-linked recessive, on X). Sickle cell anaemia (autosomal recessive; HbS; GAG → GUG, glutamic acid → valine, at the 6th position of β-globin). Phenylketonuria (autosomal recessive). Thalassemia (autosomal recessive; reduced synthesis of α or β globin).
Sickle-cell anaemia: normal vs sickle RBCs and β-chainदात्र कोशिका अरक्तता: सामान्य बनाम हँसिया RBC और β-शृंखलाSickle-cell anaemia: normal vs sickle RBCs and β-chainNCERT Fig 4.15One base change (GAG → GUG) puts valine in place of glutamic acid at position 6 of the β-chain — RBCs become sickle-shaped.एक क्षारक बदलाव (GAG → GUG) से β-शृंखला के छठे स्थान पर ग्लूटामिक अम्ल की जगह वैलीन — RBC हँसिया जैसी हो जाती हैं।Ek base change (GAG → GUG) se β-chain ki 6th position par glutamic acid ki jagah valine — RBC sickle jaisi ho jaati hain. Chromosomal disorders
Aneuploidy (gain/loss of one chromosome), polyploidy (an entire set — common in plants). Down's syndrome: trisomy of chromosome 21 (47). Klinefelter: 47, XXY male (gynaecomastia). Turner: 45, XO female (sterile).
The concept in depth — the why and the how. Everything stays within the NCERT syllabus.
Dominance is not a 'property of the gene'; it depends on what is observed
In pea, the gene for seed shape also controls starch grain size. Looking at seed shape, round (BB, Bb) appears dominant; but looking at starch grain size, BB = large, bb = small, Bb = intermediate — i.e. incomplete dominance. So dominance depends on which phenotype of the gene product we are looking at.
ABO blood group: one example, two concepts
Gene I has three alleles — IA, IB, i → multiple allelism (3 in the population, but only 2 in one person). When IA and IB are together, both are expressed (AB) → co-dominance. This gives 6 genotypes and 4 phenotypes (A, B, AB, O). Children of IAi × IBi parents can have all four blood groups.
ABO blood groups: multiple alleles and co-dominanceABO रुधिर वर्ग: बहुयुग्मविकल्पी और सह-प्रभाविताABO blood groups: multiple alleles and co-dominanceNCERT Table 4.23 alleles (Iᴬ, Iᴮ, i) → 6 genotypes → 4 blood groups. Iᴬ and Iᴮ are dominant over i; together (AB) both show = co-dominance.3 युग्मविकल्पी (Iᴬ, Iᴮ, i) → 6 जीनोटाइप → 4 रुधिर वर्ग। Iᴬ, Iᴮ, i पर प्रभावी; साथ हों (AB) तो दोनों दिखते हैं = सह-प्रभाविता।3 alleles (Iᴬ, Iᴮ, i) → 6 genotypes → 4 blood groups. Iᴬ aur Iᴮ, i par dominant; dono saath (AB) to dono dikhte hain = co-dominance. How did linkage cause deviation from Mendel's 9:3:3:1?
Mendel's traits were on separate chromosomes, so independent assortment occurred. Morgan observed in Drosophila that genes located close together on the same chromosome mostly go together (linkage), and parental combinations appear more frequently. White eye–yellow body showed only 1.3% recombination, whereas white eye–miniature wing showed 37.2% — the farther apart the genes, the greater the recombination. Using this idea, Sturtevant made gene maps.
Dihybrid cross (9:3:3:1)द्विसंकर संकरण (9:3:3:1)Dihybrid cross (9:3:3:1)NCERT Fig 4.7Two traits sort independently: F2 gives 9 : 3 : 3 : 1 — basis of the law of independent assortment.दो लक्षण स्वतंत्र रूप से बँटते हैं: F2 में 9 : 3 : 3 : 1 — स्वतंत्र अपव्यूहन के नियम का आधार।Do traits alag-alag bat-te hain: F2 mein 9 : 3 : 3 : 1 — law of independent assortment ka aadhaar. Trick for reading a pedigree
If two normal parents have an affected child → the trait is recessive. If the trait appears mostly in males and all sons of an affected father are normal → suspect X-linked recessive (e.g. haemophilia, colour blindness). Pedigree analysis is essential because controlled crosses cannot be performed on humans.
Symbols used in human pedigree analysisमानव वंशावली विश्लेषण में प्रयुक्त प्रतीकSymbols used in human pedigree analysisNCERT Fig 4.13 (symbols)Learn these symbols first: square = male, circle = female, shaded = affected, double line = marriage between relatives.पहले ये प्रतीक याद करें: वर्ग = नर, वृत्त = मादा, भरा = प्रभावित, दोहरी रेखा = रिश्तेदारों में विवाह।Pehle ye symbols yaad kijiye: square = male, circle = female, shaded = affected, double line = relatives mein shaadi. Sickle-cell anaemia: one base, a major disease
At the 6th position of the β-globin chain, glutamic acid is replaced by valine, because the GAG codon in the gene changes to GUG (point mutation). Under low oxygen tension, RBCs become sickle-shaped. It is autosomal recessive — HbAHbS are carriers, HbSHbS are affected. This links directly to the genetic code of Chapter 5.
Sickle-cell anaemia: normal vs sickle RBCs and β-chainदात्र कोशिका अरक्तता: सामान्य बनाम हँसिया RBC और β-शृंखलाSickle-cell anaemia: normal vs sickle RBCs and β-chainNCERT Fig 4.15One base change (GAG → GUG) puts valine in place of glutamic acid at position 6 of the β-chain — RBCs become sickle-shaped.एक क्षारक बदलाव (GAG → GUG) से β-शृंखला के छठे स्थान पर ग्लूटामिक अम्ल की जगह वैलीन — RBC हँसिया जैसी हो जाती हैं।Ek base change (GAG → GUG) se β-chain ki 6th position par glutamic acid ki jagah valine — RBC sickle jaisi ho jaati hain. Aneuploidy vs polyploidy
Failure of chromatids to separate during cell division (non-disjunction) causes gain or loss of a chromosome → aneuploidy: Down's (trisomy 21), Klinefelter (47, XXY), Turner (45, XO). Failure of cytokinesis increases the whole set → polyploidy, which is seen more often in plants.
Common confusions — cleared up
Incomplete dominance vs Co-dominance
Incomplete dominance: the heterozygote shows an intermediate phenotype (pink in snapdragon). Co-dominance: both alleles are fully expressed together (AB blood group).
Incomplete dominance in snapdragonस्नैपड्रैगन में अपूर्ण प्रभाविताIncomplete dominance in snapdragonNCERT Fig 4.6RR red × rr white → F1 Rr pink (in between). F2: 1 red : 2 pink : 1 white — phenotype ratio = genotype ratio.RR लाल × rr सफ़ेद → F1 Rr गुलाबी (बीच का)। F2: 1 लाल : 2 गुलाबी : 1 सफ़ेद — फीनोटाइप अनुपात = जीनोटाइप अनुपात।RR red × rr white → F1 Rr pink (beech ka). F2: 1 red : 2 pink : 1 white — phenotype ratio = genotype ratio. ABO blood groups: multiple alleles and co-dominanceABO रुधिर वर्ग: बहुयुग्मविकल्पी और सह-प्रभाविताABO blood groups: multiple alleles and co-dominanceNCERT Table 4.23 alleles (Iᴬ, Iᴮ, i) → 6 genotypes → 4 blood groups. Iᴬ and Iᴮ are dominant over i; together (AB) both show = co-dominance.3 युग्मविकल्पी (Iᴬ, Iᴮ, i) → 6 जीनोटाइप → 4 रुधिर वर्ग। Iᴬ, Iᴮ, i पर प्रभावी; साथ हों (AB) तो दोनों दिखते हैं = सह-प्रभाविता।3 alleles (Iᴬ, Iᴮ, i) → 6 genotypes → 4 blood groups. Iᴬ aur Iᴮ, i par dominant; dono saath (AB) to dono dikhte hain = co-dominance. Pleiotropy vs Polygenic inheritance
Pleiotropy: one gene → many traits (phenylketonuria). Polygenic: many genes → one trait (human skin colour, height).
Test cross vs Back cross
A test cross is always done with a homozygous recessive parent, to find out the unknown genotype (1:1 or all dominant).
Who determines sex in birds?
In birds, females are heterogametic (ZW) and males are homogametic (ZZ), so the sex is determined by the ovum — the opposite of humans.
Video
▶ Principles of Inheritance and Variation Class 12 Biology | Chapter 4 One Shot NCERT · 50 min
1-minute revision Shorts
Diagrams (tap & zoom)
All 7 diagrams of this chapter — tap one to open itइस अध्याय के सभी 7 डायग्राम — खोलने के लिए टैप करेंIs chapter ke saare 7 diagrams — kholne ke liye tap kijiye
Monohybrid cross (Punnett square)एकसंकर संकरण (पुनेट वर्ग)Figs 4.3–4.4
Dihybrid cross (9:3:3:1)द्विसंकर संकरण (9:3:3:1)Fig 4.7
Sex determination in humans (XY)मनुष्य में लिंग निर्धारण (XY)Fig 4.12
Incomplete dominance in snapdragonस्नैपड्रैगन में अपूर्ण प्रभाविताFig 4.6
ABO blood groups: multiple alleles and co-dominanceABO रुधिर वर्ग: बहुयुग्मविकल्पी और सह-प्रभाविताTable 4.2
Symbols used in human pedigree analysisमानव वंशावली विश्लेषण में प्रयुक्त प्रतीकFig 4.13 (symbols)
Sickle-cell anaemia: normal vs sickle RBCs and β-chainदात्र कोशिका अरक्तता: सामान्य बनाम हँसिया RBC और β-शृंखलाFig 4.15Detail: In Mendel's pea plant, T (tall) is dominant and t (dwarf) is recessive. In F2, the phenotypic ratio is 3:1 and the genotypic ratio is 1:2:1 — this demonstrates the Law of Segregation (alleles separate during gamete formation).
Original SLH diagram · Punnett square for Tt x Tt showing TT, Tt, Tt and tt; phenotypic ratio 3 tall : 1 dwarf, genotypic ratio 1:2:1.
Important questions with answers
Q1. What are the phenotypic and genotypic ratios of a monohybrid cross?
In the F2 generation, the phenotypic ratio is 3:1 (3 tall : 1 dwarf) and the genotypic ratio is 1:2:1 (1 TT : 2 Tt : 1 tt).
Q2. What is co-dominance? Give an example.
When both alleles in a heterozygote express their effects equally, it is called co-dominance. Example: in the ABO blood group, Iᴬ and Iᴮ are both co-dominant, so a person with IᴬIᴮ has blood group AB.
Q3. What is Down's syndrome?
It is caused by an extra copy of chromosome number 21 (trisomy 21), giving a total of 47 chromosomes. Symptoms: short stature, small round head, furrowed tongue, partially open mouth, delayed physical and mental development. It was described by Langdon Down in 1866.
Q4. How is sex determined in the honey bee?
The honey bee has a haplodiploid system. A fertilised egg develops into a female (queen or worker, diploid, 32 chromosomes), and an unfertilised egg develops by parthenogenesis into a male drone (haploid, 16 chromosomes).
UP Board previous year questions (2022–2026)
These questions are from real UP Board Intermediate papers (copies from a third-party archive, read and verified by SLH). Also shown: in how many 2022–2026 papers (different sets) a question from this topic appeared. See year-wise papers →
- “How many years did Gregor Mendel conduct experiments on garden pea plants? (A) Five (B) Two (C) Seven (D) Eleven”
UP Board 20261 marksQuestions from this topic: 20 papers (2022, 2023, 2024, 2025, 2026) - “Describe chromosomal aberration with examples.”
UP Board 20265 marksQuestions from this topic: 17 papers (2022, 2023, 2024, 2025, 2026) - “Give one example of a sex-linked recessive disorder.”
UP Board 20261 marksQuestions from this topic: 12 papers (2022, 2023, 2024, 2025, 2026) - “Describe the mechanism of sex determination in honey bees and birds.”
UP Board 20265 marksQuestions from this topic: 11 papers (2022, 2023, 2024, 2025, 2026) - “Sickle cell anaemia disease is an example of which type of mutation? (A) Point mutation (B) Euploidy (C) Deletion (D) Translocation”
UP Board 20261 marksQuestions from this topic: 11 papers (2022, 2023, 2024, 2025, 2026) - “The phenotypic ratio of classical Mendelian dihybrid cross is: (A) 1:2:1 (B) 3:1 (C) 9:7 (D) 9:3:3:1”
UP Board 20261 marksQuestions from this topic: 8 papers (2022, 2023, 2024, 2025, 2026) - “Describe allele and multiple allele.”
UP Board 20263 marksQuestions from this topic: 8 papers (2022, 2023, 2024, 2025, 2026)
Practice quiz
Tap an option — get instant right/wrong feedback and an explanation. Wrong answers are saved in "My mistakes".
1. What is the F2 phenotypic ratio in a monohybrid cross?
2. What type of inheritance does flower colour show in snapdragon?
3. How many genotypes are possible in the ABO blood group?
4. Who discovered linkage?
5. What is the karyotype in Turner's syndrome?
6. In sickle cell anaemia, what changes at the 6th position of β-globin?
7. What type of gametes does the female produce in birds?
8. F2 phenotypic ratio of a dihybrid cross?
Quick revision checklist
Before the exam — try explaining each topic aloud for 1 minute. If you get stuck, reread it in the notes above.
- Heredity & variation
- Monohybrid cross
- Mendel's laws
- Test cross
- Incomplete dominance
- Co-dominance & multiple alleles
- Pleiotropy & polygenic
- Dihybrid cross
- Chromosomal theory
- Sex determination
- Mutation & pedigree
- Mendelian disorders
- Chromosomal disorders

